/* The following C / C++ program require user to enter the elements
of arrays having equal number of array elements. Equal number of array
elements are required in this program. This program can be extended to
any of the data type & to the 'n' number of arrays simultaneously*/
Code:
#include<iostream>
#include<conio.h>
using namespace std;
void main ()
{
int long a[100],b[100],c[100];
int d=0,n;
cout<<"Number of Elements in Arrays: ";
cin>>n;
cout<<"Enter For Array 1"<<endl;
while (d<n)
{
cout<<"Enter the element number "<<d+1<<" : ";
cin>>a[d];
d=d+1;
}
d=0;
cout<<"Enter For Array 2"<<endl;
while (d<n)
{
cout<<"Enter the element number "<<d+1<<" : ";
cin>>b[d];
d=d+1;
}
d=0;
while (d<n)
{
c[d]=a[d]*b[d];
d=d+1;
}
d=0;
cout<<"\nResult of element wise product of array elements:\n";
while (d<n)
{
cout<<c[d]<<"\t";
d=d+1;
}
getche();
}
Output
Code:
#include<iostream>
#include<conio.h>
using namespace std;
void main ()
{
int long a[100],b[100],c[100];
int d=0,n;
cout<<"Number of Elements in Arrays: ";
cin>>n;
cout<<"Enter For Array 1"<<endl;
while (d<n)
{
cout<<"Enter the element number "<<d+1<<" : ";
cin>>a[d];
d=d+1;
}
d=0;
cout<<"Enter For Array 2"<<endl;
while (d<n)
{
cout<<"Enter the element number "<<d+1<<" : ";
cin>>b[d];
d=d+1;
}
d=0;
while (d<n)
{
c[d]=a[d]*b[d];
d=d+1;
}
d=0;
cout<<"\nResult of element wise product of array elements:\n";
while (d<n)
{
cout<<c[d]<<"\t";
d=d+1;
}
getche();
}
Output
Output of C / C++ Program to calculate element wise product of 2 arrays : element wise multiplication |
0 comments:
Post a Comment